(3y+4)(y^2-3y-4)=0

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Solution for (3y+4)(y^2-3y-4)=0 equation: 


Simplifying
(3y + 4)(y2 + -3y + -4) = 0

Reorder the terms:
(4 + 3y)(y2 + -3y + -4) = 0

Reorder the terms:
(4 + 3y)(-4 + -3y + y2) = 0

Multiply (4 + 3y) * (-4 + -3y + y2)
(4(-4 + -3y + y2) + 3y * (-4 + -3y + y2)) = 0
((-4 * 4 + -3y * 4 + y2 * 4) + 3y * (-4 + -3y + y2)) = 0
((-16 + -12y + 4y2) + 3y * (-4 + -3y + y2)) = 0
(-16 + -12y + 4y2 + (-4 * 3y + -3y * 3y + y2 * 3y)) = 0
(-16 + -12y + 4y2 + (-12y + -9y2 + 3y3)) = 0

Reorder the terms:
(-16 + -12y + -12y + 4y2 + -9y2 + 3y3) = 0

Combine like terms: -12y + -12y = -24y
(-16 + -24y + 4y2 + -9y2 + 3y3) = 0

Combine like terms: 4y2 + -9y2 = -5y2
(-16 + -24y + -5y2 + 3y3) = 0

Solving
-16 + -24y + -5y2 + 3y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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